20=-16t^2+88t+6

Solution for 20=-16t^2+88t+6 equation:

20=-16t^2+88t+6

We move all terms to the left:

20-(-16t^2+88t+6)=0

We get rid of parentheses

16t^2-88t-6+20=0

We add all the numbers together, and all the variables

16t^2-88t+14=0

a = 16; b = -88; c = +14;
Δ = b2-4ac
Δ = -882-4·16·14
Δ = 6848
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6848}=\sqrt{64*107}=\sqrt{64}*\sqrt{107}=8\sqrt{107}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-88)-8\sqrt{107}}{2*16}=\frac{88-8\sqrt{107}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-88)+8\sqrt{107}}{2*16}=\frac{88+8\sqrt{107}}{32}
$